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CONTINUOUS ASSESSMENT: Ordinary exam:
A continuous assessment learning scheme will be offered to the students:
- An exam will be held related to the theory (A sessions). - The student has to solve C languaje programming exercices (A sessions).
- The student has to elaborate a report describing the project (B and C sessions).
Teachers will speak in spanish or galician language. Exams will be written in spanish.
The exam date will be specified in the academic calendar. A minimum score (5 out of 10) is required in order to get a pass.
The project will be comprised in two parts. In the first, the student will work with basic peripherals (25% of the final mark) and in the second the student will work with complex peripherals (25% of the final mark). In order to assess the project, the lecturer will consider the work in the laboratory and the student’s behaviorfor the first part and the quality of the final report (40%) and the work in the laboratory and the student’s behavior (60%) in the second.
To pass the subject, it is necessary that the mark of the exam, the C programming exercices and the project are equal or greater than 5 over 10.
The final mark (FM) is calculated as the weighted average of the three individual marks. The formula will apply a weight of 30% to the theory mark (TM), 20% to the C programming exercices mark (CM) and a 50 % to the project mark (PM):
FM = 0,3*TM + 0,2*CM + 0,5*PM (1)
The mínimum passing score required in order to get a pass in the subject is 5. In case the students do not pass
any of the tasks of the subject, the final mark (FM2) will be:
FM2= Minimum{4.9, FM} Being FM the mark applying (1).
One month after the start of the new school year, when a student attend the three first laboratory classes it is considered that he/she choose the continuous assessment scheme. Extraordinary exam:
The assessment policy in this call follows the same scheme, the students have to take the exam and present the monitored project and the C programming exercices.
GLOBAL ASSESSMEN AND END-OF-PROGRAM EXAM: Students who refuse the continuous assessment scheme will be assessed by means of a final exam to evaluate the theory. The exam will be the same for them as for the students who follow the continuous scheme.
The assessment of the laboratory for these students will be carried out by means of a laboratory exam. In this exam, the student has to solve asembly and C languaje programming exercices. The date will be fixed within the examination period. In this case, the final mark (FM) is calculated as the weighted average of the two individual marks. The formula will apply a weight of 20% to the theory mark (TM) and a 70% to the laboratory mark (LM):
FM = 0,3*TM + 0,7*LM (2) To pass the subject, it is necessary that the mark of each of the exams are equal or greater than 5 over 10. The minimum
passing score required in order to get a pass in the subject is 5. In case the students do not pass any of the tasks of the subject, the final mark (FM2) will be:
FM2= Minimum{4.9, FM}
Being FM the mark applying (2).
IMPORTANT REMARK:
Students who refuse the continuous assessment scheme have to contact the lecturer at least two weeks before the exam date. |
